3.692 \(\int x (a+b x^2)^{4/3} \, dx\)

Optimal. Leaf size=18 \[ \frac {3 \left (a+b x^2\right )^{7/3}}{14 b} \]

[Out]

3/14*(b*x^2+a)^(7/3)/b

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Rubi [A]  time = 0.00, antiderivative size = 18, normalized size of antiderivative = 1.00, number of steps used = 1, number of rules used = 1, integrand size = 13, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.077, Rules used = {261} \[ \frac {3 \left (a+b x^2\right )^{7/3}}{14 b} \]

Antiderivative was successfully verified.

[In]

Int[x*(a + b*x^2)^(4/3),x]

[Out]

(3*(a + b*x^2)^(7/3))/(14*b)

Rule 261

Int[(x_)^(m_.)*((a_) + (b_.)*(x_)^(n_))^(p_), x_Symbol] :> Simp[(a + b*x^n)^(p + 1)/(b*n*(p + 1)), x] /; FreeQ
[{a, b, m, n, p}, x] && EqQ[m, n - 1] && NeQ[p, -1]

Rubi steps

\begin {align*} \int x \left (a+b x^2\right )^{4/3} \, dx &=\frac {3 \left (a+b x^2\right )^{7/3}}{14 b}\\ \end {align*}

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Mathematica [A]  time = 0.00, size = 18, normalized size = 1.00 \[ \frac {3 \left (a+b x^2\right )^{7/3}}{14 b} \]

Antiderivative was successfully verified.

[In]

Integrate[x*(a + b*x^2)^(4/3),x]

[Out]

(3*(a + b*x^2)^(7/3))/(14*b)

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fricas [B]  time = 0.65, size = 32, normalized size = 1.78 \[ \frac {3 \, {\left (b^{2} x^{4} + 2 \, a b x^{2} + a^{2}\right )} {\left (b x^{2} + a\right )}^{\frac {1}{3}}}{14 \, b} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x*(b*x^2+a)^(4/3),x, algorithm="fricas")

[Out]

3/14*(b^2*x^4 + 2*a*b*x^2 + a^2)*(b*x^2 + a)^(1/3)/b

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giac [A]  time = 0.63, size = 14, normalized size = 0.78 \[ \frac {3 \, {\left (b x^{2} + a\right )}^{\frac {7}{3}}}{14 \, b} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x*(b*x^2+a)^(4/3),x, algorithm="giac")

[Out]

3/14*(b*x^2 + a)^(7/3)/b

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maple [A]  time = 0.00, size = 15, normalized size = 0.83 \[ \frac {3 \left (b \,x^{2}+a \right )^{\frac {7}{3}}}{14 b} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(x*(b*x^2+a)^(4/3),x)

[Out]

3/14*(b*x^2+a)^(7/3)/b

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maxima [A]  time = 1.33, size = 14, normalized size = 0.78 \[ \frac {3 \, {\left (b x^{2} + a\right )}^{\frac {7}{3}}}{14 \, b} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x*(b*x^2+a)^(4/3),x, algorithm="maxima")

[Out]

3/14*(b*x^2 + a)^(7/3)/b

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mupad [B]  time = 4.99, size = 14, normalized size = 0.78 \[ \frac {3\,{\left (b\,x^2+a\right )}^{7/3}}{14\,b} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(x*(a + b*x^2)^(4/3),x)

[Out]

(3*(a + b*x^2)^(7/3))/(14*b)

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sympy [A]  time = 1.37, size = 65, normalized size = 3.61 \[ \begin {cases} \frac {3 a^{2} \sqrt [3]{a + b x^{2}}}{14 b} + \frac {3 a x^{2} \sqrt [3]{a + b x^{2}}}{7} + \frac {3 b x^{4} \sqrt [3]{a + b x^{2}}}{14} & \text {for}\: b \neq 0 \\\frac {a^{\frac {4}{3}} x^{2}}{2} & \text {otherwise} \end {cases} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x*(b*x**2+a)**(4/3),x)

[Out]

Piecewise((3*a**2*(a + b*x**2)**(1/3)/(14*b) + 3*a*x**2*(a + b*x**2)**(1/3)/7 + 3*b*x**4*(a + b*x**2)**(1/3)/1
4, Ne(b, 0)), (a**(4/3)*x**2/2, True))

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